Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 15:42Z
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
∫₀^∞ e^(-t²) dt = √π / 2
52K
det| 2 2 ; 6 3 | = -6
det| 11 5 ; 0 12 | = 132
90K
det| 2 7 ; 7 3 | = -43
91K
d/dφ [φ^6] = 6φ^5
det| 10 3 ; 1 11 | = 107
det| 7 4 ; 4 8 | = 40
197K
det| 11 7 ; 4 12 | = 104
∑_{k=1}^{n} k = n(n+1)/2
262K
∫₀^∞ e^(-φ²) dφ = √π / 2
196K