Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:40Z
∑_{k=1}^{n} k = n(n+1)/2
det| 12 5 ; 4 13 | = 136
∫₀^∞ e^(-n²) dn = √π / 2
91K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
100K
∑_{k=1}^{n} k = n(n+1)/2
50K
∑_{k=1}^{n} k = n(n+1)/2
196K