Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:38Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
8K
E = mc²
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
102K
∑_{k=1}^{n} k = n(n+1)/2
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 8 5 ; 3 9 | = 57
264K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
276K
∇ × E = −∂B/∂t
det| 7 4 ; 4 8 | = 40
257K
det| 3 3 ; 4 4 | = 0
250K
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂