Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:26Z
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
244K
6ω² + 3ω + 2 = 0
det| 7 4 ; 4 8 | = 40
90K
∑_{k=1}^{n} k = n(n+1)/2
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 8 3 ; 4 9 | = 60
Fe₂O₃ + 3CO → 2Fe + 3CO₂
197K
9x² + 3x + 6 = 0