Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:37Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
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E = mc²
det| 5 3 ; 2 6 | = 24
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\oint_C \vec{F}\cdot d\vec{r} = 0
det| 9 4 ; 1 10 | = 86
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\oint_C \vec{F}\cdot d\vec{r} = 0
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∇ × E = −∂B/∂t
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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λ = h/p
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CaCO₃ → CaO + CO₂