Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:42Z
8θ² + 4θ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
∇²α = 0
det| 11 5 ; 0 12 | = 132
91K
det| 5 6 ; 5 6 | = 0
det| 11 9 ; 5 12 | = 87
50K
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
137K
det| 7 4 ; 4 8 | = 40
197K
d/dn [n^5] = 5n^4
det| 8 5 ; 3 9 | = 57
196K
∑_{k=1}^{n} k = n(n+1)/2