Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:36Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
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E = mc²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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\oint_C \vec{F}\cdot d\vec{r} = 0
det| 7 4 ; 4 8 | = 40
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∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 10 5 ; 4 11 | = 90
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λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CaCO₃ → CaO + CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1