Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:42Z
8θ² + 4θ + 7 = 0
∇²α = 0
det| 5 6 ; 5 6 | = 0
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
137K
d/dn [n^5] = 5n^4
∫₀^∞ e^(-β²) dβ = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
λ = h/p
det| 7 5 ; 0 8 | = 56
det| 6 8 ; 4 7 | = 10