Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:38Z
∑_{k=1}^{n} k = n(n+1)/2
det| 1 2 ; 7 2 | = -12
244K
∫₀^∞ e^(-x²) dx = √π / 2
52K
6ω² + 3ω + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
196K
∫₀^∞ e^(-α²) dα = √π / 2
218K