Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:17Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
\oint_C \vec{F}\cdot d\vec{r} = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
∇ × E = −∂B/∂t
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
257K
det| 7 4 ; 4 8 | = 40
250K
λ = h/p
\oint_C \vec{F}\cdot d\vec{r} = 0
62K
d/dθ [θ^7] = 7θ^6
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂