Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 06:01Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-x²) dx = √π / 2
8K
det| 5 9 ; 4 6 | = -6
∑_{k=1}^{n} k = n(n+1)/2
102K
F = G m₁m₂ / r²
det| 7 4 ; 4 8 | = 40
276K
9ω² + 3ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
257K
9θ² + 8θ + 7 = 0
det| 4 8 ; 3 5 | = -4
62K
∑_{k=1}^{n} k = n(n+1)/2
256K