Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:39Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∫₀^∞ e^(-θ²) dθ = √π / 2
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det| 9 9 ; 5 10 | = 45
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E = mc²
∫₀^∞ e^(-y²) dy = √π / 2
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det| 9 4 ; 1 10 | = 86
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\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
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λ = h/p
\lim_{t\to 0} \frac{\sin t}{t} = 1
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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