Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:08Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 7 4 ; 4 8 | = 40
276K
∇ × E = −∂B/∂t
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
257K
CH₄ + 2O₂ → CO₂ + 2H₂O
250K
λ = h/p
det| 2 7 ; 7 3 | = -43
62K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CaCO₃ → CaO + CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1