Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:37Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 2 ; 3 5 | = 14
52K
6ω² + 3ω + 2 = 0
det| 10 3 ; 4 11 | = 98
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 11 2 ; 5 12 | = 122
137K
det| 9 4 ; 1 10 | = 86
197K
∫₀^∞ e^(-n²) dn = √π / 2
262K
∫₀^∞ e^(-t²) dt = √π / 2
196K
∑_{k=1}^{n} k = n(n+1)/2
218K