Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 00:35Z
11y² + 4y + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
∑_{k=1}^{n} k = n(n+1)/2
8K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
102K
det| 7 4 ; 4 8 | = 40
57K
det| 12 1 ; 0 13 | = 156
CaCO₃ → CaO + CO₂
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
257K
∑_{k=1}^{n} k = n(n+1)/2
250K
E = mc²
det| 4 8 ; 3 5 | = -4
256K
CH₄ + 2O₂ → CO₂ + 2H₂O
2H₂ + O₂ → 2H₂O