Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:19Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
6ω² + 3ω + 2 = 0
det| 7 4 ; 4 8 | = 40
90K
det| 11 5 ; 0 12 | = 132
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
197K