Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 01:52Z
∇²γ = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
6t² + 5t + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
91K
N₂ + 3H₂ ⇌ 2NH₃
det| 9 4 ; 1 10 | = 86
50K
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
det| 8 2 ; 7 9 | = 58
137K
10φ² + 3φ + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
262K
∑_{k=1}^{n} k = n(n+1)/2
196K
det| 11 1 ; 1 12 | = 131