Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:08Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
\oint_C \vec{F}\cdot d\vec{r} = 0
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E = mc²
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
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∇ × E = −∂B/∂t
∫₀^∞ e^(-φ²) dφ = √π / 2
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λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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