Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 05:59Z
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
91K
det| 7 5 ; 1 8 | = 51
det| 7 4 ; 4 8 | = 40
50K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 2 4 ; 4 3 | = -10
197K
∫₀^∞ e^(-z²) dz = √π / 2
λ = h/p
∂ψ/∂θ = 9ψ
3t² + 6t + 2 = 0