Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:17Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 2 ; 3 5 | = 14
244K
6ω² + 3ω + 2 = 0
∫₀^∞ e^(-n²) dn = √π / 2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
50K
det| 8 3 ; 4 9 | = 60
det| 9 4 ; 1 10 | = 86
137K
det| 4 8 ; 3 5 | = -4
197K
9x² + 3x + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
262K
det| 8 4 ; 1 9 | = 68
9ψ² + 3ψ + 3 = 0
det| 6 8 ; 7 7 | = -14
F = G m₁m₂ / r²