Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:51Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
6ω² + 3ω + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
100K
det| 8 3 ; 4 9 | = 60
det| 10 5 ; 4 11 | = 90
137K
9x² + 3x + 6 = 0
9ψ² + 3ψ + 3 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
218K
det| 6 8 ; 7 7 | = -14