Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 21:59Z
4ω² + 7ω + 3 = 0
F = ma
∑_{k=1}^{n} k = n(n+1)/2
102K
11t² + 5t + 7 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
264K
∂t/∂θ = 3t
∑_{k=1}^{n} k = n(n+1)/2
257K
det| 9 4 ; 1 10 | = 86
250K
∫₀^∞ e^(-γ²) dγ = √π / 2