Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:42Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 7 4 ; 4 8 | = 40
52K
det| 12 5 ; 4 13 | = 136
det| 2 4 ; 4 3 | = -10
90K
det| 10 7 ; 3 11 | = 89
91K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-n²) dn = √π / 2
100K
det| 4 9 ; 7 5 | = -43
det| 1 1 ; 3 2 | = -1
∑_{k=1}^{n} k = n(n+1)/2
262K
det| 7 7 ; 4 8 | = 28
196K
det| 12 9 ; 3 13 | = 129