Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:08Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
8K
E = mc²
\oint_C \vec{F}\cdot d\vec{r} = 0
\lim_{x\to 0} \frac{\sin x}{x} = 1
264K
d/dz [z^11] = 11z^10
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∇ × E = −∂B/∂t
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
257K
det| 9 4 ; 1 10 | = 86
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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
256K