Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 01:46Z
∇²γ = 0
∑_{k=1}^{n} k = n(n+1)/2
52K
6t² + 5t + 2 = 0
∫₀^∞ e^(-n²) dn = √π / 2
91K
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-α²) dα = √π / 2
100K
det| 7 4 ; 4 8 | = 40
50K
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
10φ² + 3φ + 2 = 0
det| 11 1 ; 1 12 | = 131
det| 3 3 ; 4 4 | = 0
218K
3φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
ω = 2πf