Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 01:51Z
∇²γ = 0
det| 1 4 ; 2 2 | = -6
244K
∑_{k=1}^{n} k = n(n+1)/2
52K
6t² + 5t + 2 = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
100K
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
137K
10φ² + 3φ + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
196K