Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 22:23Z
11z² + 7z + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
479K
\oint_C \vec{F}\cdot d\vec{r} = 0
8K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
57K
det| 3 6 ; 6 4 | = -24
det| 11 2 ; 5 12 | = 122
264K
det| 8 2 ; 7 9 | = 58
276K
ΔS ≥ 0
\oint_C \vec{F}\cdot d\vec{r} = 0
257K
∇²γ = 0
∑_{k=1}^{n} k = n(n+1)/2
62K
det| 7 4 ; 4 8 | = 40
256K
F = G m₁m₂ / r²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
46K
det| 7 2 ; 3 8 | = 50
164K
\oint_C \vec{F}\cdot d\vec{r} = 0
6z² + 3z + 0 = 0