Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:37Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
∫₀^∞ e^(-n²) dn = √π / 2
102K
CH₄ + 2O₂ → CO₂ + 2H₂O
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 9 6 ; 0 10 | = 90
264K
det| 4 6 ; 4 5 | = -4
276K
∇ × E = −∂B/∂t
det| 2 7 ; 7 3 | = -43
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
250K
λ = h/p
det| 9 4 ; 1 10 | = 86
256K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CaCO₃ → CaO + CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1