Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:21Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
52K
6ω² + 3ω + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
90K
∫₀^∞ e^(-n²) dn = √π / 2
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 6 4 ; 4 7 | = 26
100K
det| 8 3 ; 4 9 | = 60
9x² + 3x + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
262K
∑_{k=1}^{n} k = n(n+1)/2
218K