Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:08Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
479K
E = mc²
\frac{2}{2} \sum_{i=1}^{n} i^{2}
102K
det| 7 4 ; 4 8 | = 40
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 9 9 ; 5 10 | = 45
276K
∇ × E = −∂B/∂t
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
257K
λ = h/p
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
62K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∫₀^∞ e^(-x²) dx = √π / 2
46K
CaCO₃ → CaO + CO₂