Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:50Z
8θ² + 4θ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
∇²α = 0
det| 5 6 ; 5 6 | = 0
det| 9 4 ; 1 10 | = 86
100K
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
137K
d/dn [n^5] = 5n^4
det| 10 5 ; 4 11 | = 90
262K
det| 8 2 ; 7 9 | = 58
196K
∑_{k=1}^{n} k = n(n+1)/2
λ = h/p