Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:26Z
∑_{k=1}^{n} k = n(n+1)/2
det| 10 3 ; 4 11 | = 98
52K
6ω² + 3ω + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 7 4 ; 4 8 | = 40
100K
det| 5 3 ; 2 6 | = 24
50K
det| 8 3 ; 4 9 | = 60
∫₀^∞ e^(-y²) dy = √π / 2
137K
∑_{k=1}^{n} k = n(n+1)/2
197K
CH₄ + 2O₂ → CO₂ + 2H₂O
218K