Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 01:52Z
∇²γ = 0
∫₀^∞ e^(-n²) dn = √π / 2
244K
6t² + 5t + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-φ²) dφ = √π / 2
137K
det| 9 4 ; 1 10 | = 86
197K
∫₀^∞ e^(-t²) dt = √π / 2
196K
∑_{k=1}^{n} k = n(n+1)/2
218K
det| 4 8 ; 3 5 | = -4
299K