Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:27Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 12 9 ; 5 13 | = 111
52K
6ω² + 3ω + 2 = 0
∫₀^∞ e^(-α²) dα = √π / 2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
100K
det| 8 3 ; 4 9 | = 60
det| 4 8 ; 3 5 | = -4
137K
det| 7 4 ; 4 8 | = 40
197K