Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:09Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
479K
∑_{k=1}^{n} k = n(n+1)/2
8K
E = mc²
∫₀^∞ e^(-n²) dn = √π / 2
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 7 4 ; 4 8 | = 40
276K
∇ × E = −∂B/∂t
λ = h/p
\frac{8}{6} \sum_{i=1}^{n} i^{2}
62K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
\lim_{t\to 0} \frac{\sin t}{t} = 1
46K
CaCO₃ → CaO + CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1
\lim_{x\to 0} \frac{\sin x}{x} = 1