Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:27Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 8 3 ; 4 9 | = 60
9x² + 3x + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
262K
det| 9 9 ; 5 10 | = 45
196K