Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-25 08:19Z
det| 10 8 ; 6 11 | = 62
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-y²) dy = √π / 2
390K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
313K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
λ = h/p
\oint_C \vec{F}\cdot d\vec{r} = 0
428K
∂θ/∂x = 3θ
∂θ/∂ω = 8θ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O